Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Review Exercises: 1

Answer

see table
1514010843

Work Step by Step

$\bf{\text{Solution Outline:}}$ Complete the table by substituting the given value of the variable in the given equation, $ 3x+2y=10 .$ $\bf{\text{Solution Details:}}$ If $ x=0 ,$ then \begin{array}{l}\require{cancel} 3x+2y=10 \\\\ 3(0)+2y=10 \\\\ 0+2y=10 \\\\ 2y=10 \\\\ y=\dfrac{10}{2} \\\\ y=5 .\end{array} If $ y=0 ,$ then \begin{array}{l}\require{cancel} 3x+2y=10 \\\\ 3x+2(0)=10 \\\\ 3x+0=10 \\\\ 3x=10 \\\\ x=\dfrac{10}{3} .\end{array} If $ x=2 ,$ then \begin{array}{l}\require{cancel} 3x+2y=10 \\\\ 3(2)+2y=10 \\\\ 6+2y=10 \\\\ 2y=10-6 \\\\ 2y=4 \\\\ y=\dfrac{4}{2} \\\\ y=2 .\end{array} If $ y=-2 ,$ then \begin{array}{l}\require{cancel} 3x+2y=10 \\\\ 3x+2(-2)=10 \\\\ 3x-4=10 \\\\ 3x=10+4 \\\\ 3x=14 \\\\ x=\dfrac{14}{3} .\end{array}
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