## Elementary Algebra

We simplify the equation by rationalizing its denominator. To rationalize the denominator, we multiply both the numerator and the denominator by $\sqrt 2$: $\frac{\sqrt 8+\sqrt {12}}{\sqrt 2}\times\frac{\sqrt 2}{\sqrt 2}$ =$\frac{\sqrt 2(\sqrt 8+\sqrt {12})}{\sqrt 2\times\sqrt 2}$ =$\frac{\sqrt 2\sqrt 8+\sqrt 2\sqrt {12}}{2}$ =$\frac{\sqrt {2\times8}+\sqrt {2\times12}}{2}$ =$\frac{\sqrt {16}+\sqrt {24}}{2}$ =$\frac{4+\sqrt {4\times6}}{2}$ =$\frac{4+2\sqrt {6}}{2}$ =$2+\sqrt {6}$ Therefore, the question statement is true.