Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.5 - Fractional Equations and Problem Solving - Problem Set 7.5 - Page 305: 22

Answer

{$-\frac{17}{48}$}

Work Step by Step

First, we add the two fractions on the left hand side of the equation by finding the LCM of the denominators of the two fractions. Upon observation, we find that the LCM of the two denominators is $6t$. Then, we cross multiply the resultant fractional equation and solve the resultant expression. Step 1: $\frac{1}{6t}-2=\frac{7}{8t}$ Step 2: $\frac{1(1)-2(6t)}{6t}=\frac{7}{8t}$ Step 3: $\frac{1-12t}{6t}=\frac{7}{8t}$ Step 4: $8t(1-12t)=7(6t)$ Step 5: $8(1-12t)=7(6)$ Step 6: $8-96t=42$ Step 7: $-96t=42-8$ Step 8: $-96t=34$ Step 9: $t=-\frac{34}{96}=-\frac{17}{48}$ Therefore, the solution set is {$-\frac{17}{48}$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.