Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.1 - Simplifying Algebraic Fractions - Problem Set 7.1: 71

Answer

$-\frac{4}{a^{3}}$

Work Step by Step

Using the rule $\frac{x^{a}}{x^{b}}=x^{a-b}$, we obtain: $\frac{28a^{2}b^{3}}{-7a^{5}b^{3}}$ $\frac{28}{-7}\times\frac{a^{2}}{a^{5}}\times\frac{b^{3}}{b^{3}}$ $=-4\times a^{2-5}\times b^{3-3}$ $=-4\times a^{-3}\times b^{0}$ $=-4\times \frac{1}{a^{3}}\times 1$ $=\frac{-4}{a^{3}}$ $=-\frac{4}{a^{3}}$
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