Answer
$(x-y)(b-c)$
Work Step by Step
Using factoring by grouping, the factored form of the given expression, $
bx-by-cx+cy
,$ is
\begin{array}{l}\require{cancel}
(bx-by)-(cx-cy)
\\\\=
b(x-y)-c(x-y)
\\\\=
(x-y)(b-c)
.\end{array}
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.1 - Factoring by Using the Distributive Property - Problem Set 6.1 - Page 242: 49
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