Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 5 - Inner Product Spaces - 5.5 Chapter Review - Additional Problems - Page 376: 1

Answer

$\theta=\arccos(\frac{5\sqrt 221}{221})$

Work Step by Step

We are given: $u=(2,3)\\ v=(4,-1)$ in $R^2$ Let $\theta$ be the angle between $u$ and $v$. We obtain: $$\cos \theta=\frac{}{||u||.||v||}\\ =\frac{2.4+3.(-1)}{\sqrt 2^2+3^2.\sqrt x4^2+(-1)^2}\\ =\frac{5}{\sqrt 221}$$ $$\rightarrow \theta=\arccos(\frac{5\sqrt 221}{221})$$
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