Answer
True
Work Step by Step
The least squares solution: $x_0=(A^TA)^{-1}A^Tb$
If A is an n×n invertible matrix then $A^T(A^T)^{-1}=(A^T)^{-1}A^T=I$
Apply to the least squares solution we have:
$x_0=(A^TA)^{-1}A^Tb$
$\rightarrow x_0=A^{-1}(A^T)^{-1}A^Tb$
$\rightarrow x_0=A^{-1}b$
Thus, the statement is true.