Answer
False
Work Step by Step
If $B_1=\{x_1,x_2\}\\
B_2=\{y_1,y_2\}$
Apply Gram- Schmidt process:
$v_1=x_1\\
v_2=x_2-\frac{}{||v_1||^2}v_1$
and $v_1=y_1\\
v_2=y_2-\frac{}{||v_1||}^2v_1$
hence $x_2-\frac{}{||v_1||^2}v_1=y_2-\frac{}{||v_1||^2}v_1\\
x_2-\frac{}{||v_1||^2}x_1=y_2-\frac{}{||v_1||^2}x_1$
This does not mean that $x_2=y_2 $