Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 5 - Inner Product Spaces - 5.3 The Gram-Schmidt Process - Problems - Page 365: 10

Answer

See below

Work Step by Step

According to Gram-Schmidt process, we have: $v_1=x_1=(1,2,3,4,5)\\ v_2=x_2-\frac{}{||v_1||^2}v_1\\ =(-7,0,1,-2,0)-\frac{)}{||(1,2,3,4,5)||^2}(1,2,3,4,5)\\ =(-7,0,1,-2,0)-\frac{(-7).1+2.0+1.3+(-2).4+0.5}{1^2+2^2+3^2+4^2+5^2}(1,2,3,4,5)\\ =(-7,0,1,-2,0)-\frac{-7+0+3-8+0}{1+4+9+16+25}(1,2,3,4,5)\\ =(-7,0,1,-2,0)+\frac{22}{55}(1,2,3,4,5)\\ =\frac{1}{55}(-373,24,91,-62,60)$ To determine an orthogonal set, we obtain: $\frac{v_1}{||v_1||}=\frac{(1,2,3,4,5)}{\sqrt 1^2+2^2+3^2+4^2+5^2}=\frac{(1,2,3,4,5)}{\sqrt 55}=\frac{1}{\sqrt 55}(1,2,3,4,5)$ $\frac{v_2}{||v_2||}=\frac{\frac{1}{55}(-373,24,91,-62,60)}{\frac{1}{55}\sqrt 155430}=\frac{1}{\sqrt 155430}(-373,24,91,-62,60)$
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