Answer
True
Work Step by Step
$w_1,w_2$ and $v$ are vectors in an inner product space $V$
We have the notation for the inner product: $P(w,v)=\frac{}{||v||^2}v$
then $P(w_1+w_2,u)=\frac{P}{||v||^2}v=\frac{+}{||v||^2}v=\frac{}{||v||^2}v+\frac{}{||v||^2}v=P(w_1,v)+P(w_2,v)$
Hence, the statement is true.