Answer
See below
Work Step by Step
Let $\{u1, u2, v\}$ be linearly independent vectors in an inner product space V, and suppose that $u_1$ and $u_2$ are orthogonal.
Prove:
$\\
\leftrightarrow < v+\lambda u_1+\mu u_2,u_1>=0\\
\leftrightarrow < v+ u_1>++=0 \\
\leftrightarrow < v+ u_1>+\lambda +\mu =0 \\
\leftrightarrow < v+ u_1>+\lambda ||u_1||^2=0 \\
\rightarrow \lambda=-\frac{}{||u_1||^2}$
$\\
\leftrightarrow < v+\lambda u_1+\mu u_2,u_2>=0\\
\leftrightarrow < v+ u_2>++=0 \\
\leftrightarrow < v+ u_2>+\lambda +\mu =0 \\
\leftrightarrow < v+ u_2>+\mu ||u_2||^2=0 \\
\rightarrow \mu=-\frac{}{||u_2||^2}$