Answer
See below
Work Step by Step
Given:
$t=30\\
M=2700g\\
a=1.5\\
m_0=3g$
Obtain: $m(30)=(2700)[1-(1-\frac{3}{2700}^{\frac{1}{4}})e^{\frac{(-1.5)(30)}{4(2700)^{\frac{1}{4}}}}]^4 \approx 1271g$
The mass of the heron after 30 days is $1271$ g
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 1 - First-Order Differential Equations - 1.1 Differential Equations Everywhere - Problems - Page 13: 32
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