College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.2 - Page 537: 23

Answer

See below.

Work Step by Step

The equations according to the text: $x+y+z=16,2x+3y+4z=46, 5x-y=31$. $y=5x-31$, thus: $x+(5x-31)+z=16\\6x-31+z=16\\6x+z=47\\z=47-6x$ Thus: $2x+3(5x-31)+4(47-6x)=46\\2x+15x-93+188-24x=46\\-7x+95=46\\-7x=-49\\x=7$ Thus $y=5(7)-31=35-31=4$, $z=47-6(7)=47-42=5$
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