College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Test - Page 581: 8

Answer

$y=2(x-2)^2+3$

Work Step by Step

Use vertex form of a parabola: $$y=a(x-h)^2+k$$ Where vertex is at $(h,k)$. Substitute vertex $(2,3)$: $$y=a(x-2)^2+3$$ Now substitute one of the point on the parabola $(1,5)$: $$5=a(1-2)^2+3$$ $$5=a(-1)^2+3$$ $$5=a+3$$ $$a=2$$ So, equation becomes: $$y=2(x-2)^2+3$$
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