#### Answer

Domain: $(-\infty, +\infty)$
Range: $(-\infty, +\infty)$
Refer to the image below for the graph.

#### Work Step by Step

$f(x)=\frac{2}{3}x+2$
The x-intercept can be found by letting f(x)=0.
Here,
$0=\frac{2}{3}x+2$
$-2=\frac{2}{3}x$
$-6=2x$
$-3=x$
Hence, -3 is the x-intercept, therefore we plot (-3,0).
The y-intercept can be found by letting x=0.
Here,
$f(x)=-0+2$
$f(x)=2$
Hence, 2 is the y-intercept, therefore we plot (0, 2).
By connecting these two points by a straight line, we get the graph.
The domain is $(-\infty, \infty)$ as the function will "work" for all real x-values.
(We can see the domain on the graph too. As for every x-value we will find a corresponding point on the graph.)
The range is $(-\infty, \infty)$ as we will get all real y-values after substituting all real x-values in the function.
(We can see the domain on the graph too. As for every y-value we will find a corresponding point on the graph.)