College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Review Exercises - Page 160: 4

Answer

$$x=\frac{11p+11k}{10-a}$$

Work Step by Step

$$9x-11k-11p=xa-x$$ $$9x-xa+x=11p+11k$$ $$10x-xa=11p+11k$$ $$x(10-a)=11p+11k$$ $$x=\frac{11p+11k}{10-a}$$
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