Answer
$7$ and $-2$
Work Step by Step
The given function is
$\Rightarrow y=3x^2-15x-42$
Substitute $0$ for $y$.
$\Rightarrow 0=3x^2-15x-42$
Factor out $3$.
$\Rightarrow 0=3(x^2-5x-14)$
Factor the trinomial.
$\Rightarrow 0=3(x-7)(x+2)$
Use zero product property.
$\Rightarrow x-7=0$ or $x+2=0$
Solve for $x$.
$\Rightarrow x=7$ or $x=-2$
Hence, the zeros of the function are $7$ and $-2$.
