Answer
$\frac{1}{4y^{2}}$
Work Step by Step
$(\frac{2y^{4}}{y^{3}})^{-2}=(\frac{2y^{3}\cdot y^{1}}{y^{3}})^{-2}$
$=(2y)^{-2}=\frac{1}{(2y)^{2}}=\frac{1}{4y^{2}}$
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 7 - Polynomial Equations and Factoring - 7.2 - Multiplying Polynomials - Exercises - Page 370: 58
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