Answer
$\frac{1}{k^{12}}$
Work Step by Step
The given expression is
$=(k^4)^{-3}$
Use $a^{-n}=\frac{1}{a^n}$.
$=\frac{1}{(k^4)^{3}}$
Use $(a^{n})^m=a^{n\cdot m}$.
$=\frac{1}{k^{4\cdot 3}}$
Simplify.
$=\frac{1}{k^{12}}$.
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