Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.2 - Fractions - Exercise Set: 89

Answer

$\frac{153}{20}$

Work Step by Step

To get the answer, we subtract the fractions. $11\frac{1}{4}-3\frac{3}{5}=\frac{11*4+1}{4}-\frac{3*5+3}{5}=\frac{45}{4}-\frac{18}{5}$ Now find LCD of fractions: 20. Write fractions with LCD as denominator $\frac{45}{4}-\frac{18}{5}=\frac{45*5}{4*5}-\frac{18*4}{5*4}=\frac{225}{20}-\frac{72}{20}=\frac{225-72}{20}=\frac{153}{20}$
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