Answer
Please see the graph.
Work Step by Step
Red line: $x+2y>0$
Blue line: $x-y\le6$
To determine what sides of the lines to shade, we use a point not on the line. We can use (3,0) for the lines.
Red line:
$x+2y>0$
$3+2*0>0$
$3+0>0$
$3>0$ (true, so we shade the right side of the line)
Blue line:
$x-y\le6$
$3-0\le6$
$3\le 6$ (true, so we shade the left side of the line)
The solution area is the overlap of the two inequalities.
