#### Answer

$\frac{8x^{3}y}{20x^{2}y^{2}}$

#### Work Step by Step

$\frac{2x}{5y}$=$\frac{2x*4x^{2}y}{5y*4x^{2}y}$=
$\frac{8x^{3}y}{20x^{2}y^{2}}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{8x^{3}y}{20x^{2}y^{2}}$

$\frac{2x}{5y}$=$\frac{2x*4x^{2}y}{5y*4x^{2}y}$=
$\frac{8x^{3}y}{20x^{2}y^{2}}$

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