Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Practice: 7

$1$

Work Step by Step

$\frac{3x^2-10x+8}{7x-14} \div \frac{9x-12}{21}$ $=\frac{(3x-4)(x-2)}{7(x-2)} \times \frac{21}{3(3x-4)}$ $=\frac{(3x-4)}{7} \times \frac{7}{(3x-4)}$ $=1$

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