Answer
$1$
Work Step by Step
$\frac{3x^2-10x+8}{7x-14} \div \frac{9x-12}{21}$
$=\frac{(3x-4)(x-2)}{7(x-2)} \times \frac{21}{3(3x-4)}$
$=\frac{(3x-4)}{7} \times \frac{7}{(3x-4)}$
$=1$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Practice - Page 496: 7
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