Answer
$\frac{x-4}{9}$
Work Step by Step
$\frac{(x-4)^2}{6} \div \frac{3x-12}{2}$
$=\frac{(x-4)^2}{6} \times \frac{2}{3x-12}$
$=\frac{(x-4)^2}{6} \times \frac{2}{3(x-4)}$
$=\frac{(x-4)}{3} \times \frac{1}{3}$
$=\frac{x-4}{9}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Practice - Page 495: 5
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