#### Answer

$\frac{x-4}{9}$

#### Work Step by Step

$\frac{(x-4)^2}{6} \div \frac{3x-12}{2}$
$=\frac{(x-4)^2}{6} \times \frac{2}{3x-12}$
$=\frac{(x-4)^2}{6} \times \frac{2}{3(x-4)}$
$=\frac{(x-4)}{3} \times \frac{1}{3}$
$=\frac{x-4}{9}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{x-4}{9}$

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