Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 500: 36



Work Step by Step

$\dfrac{3x+6}{20}\div\dfrac{4x+8}{8}$ Take out common factor $3$ from the numerator of the first fraction and common factor $4$ from the numerator of the second fraction: $\dfrac{3x+6}{20}\div\dfrac{4x+8}{8}=\dfrac{3(x+2)}{20}\div\dfrac{4(x+2)}{8}=...$ Evaluate the division of the two rational expressions and simplify by removing the factors that appear both in the numerator and the denominator: $...=\dfrac{24(x+2)}{40(x+2)}=\dfrac{24}{40}=\dfrac{3}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.