Answer
$a^2(3-b)(9+3b+b^2)$
Work Step by Step
$27a^2-b^3a^2$
$a^2(27-b^3)$
$27-b^3$
$x^3-y^3=(x-y)(x^2+xy+y^2$
$27-b^3$
$27-b^3=(3-b)(3^2+3*b+b^2)$
$(3-b)(3^2+3*b+b^2)=(3-b)(9+3b+b^2)$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.5 - Factoring by Special Products - Practice - Page 446: 18
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