Answer
3(6a-5)(3a+2)
Work Step by Step
54$a^{2}$-9a-30=3(18$a^{2}$-3a-10)=3(18$a^{2}$+12a-15a-10)=
3[6a(3a+2)-5(3a+2)]=3(6a-5)(3a+2)
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.4 - Factoring Trinomials of the Form ax2+bx+c by Grouping - Exercise Set - Page 441: 33
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