Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.4 - Factoring Trinomials of the Form ax2+bx+c by Grouping - Exercise Set: 24

Answer

$(3x+2)(2x-5)$

Work Step by Step

$6x^{2}−11x−10 $ First, identify two numbers that multiply with each other to become -60, the product of the constant and coefficient of $x^{2}$ (6 × -10) and add together to become -11, the coefficient of x. From inspection, we identify these numbers as 4 and -15. Secondly split the coefficient of x into the sum of the two above numbers. $6x^{2}−11x−10 $ $=6x^{2}+(4-15)x−10 $ $=6x^{2}+4x-15x−10 $ Factorize by grouping to find the answer. $6x^{2}+4x-15x−10 $ $=2x(3x+2)-5(3x+2) $ $=(3x+2)(2x-5)$
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