Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix F - Exercise Set - Page 1012: 28



Work Step by Step

Since the triangles are similar, corresponding sides are in proportion. This means that, $\frac{7}{14}=\frac{4}{x}$ To solve the equation for $x$, we need to cross multiply: $7\times x=4\times14$ $7x=56$ $x=\frac{56}{7}=8$ Since the two unknown sides are equal, both have a length of $8$ units.
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