Answer
$(x,y) | 3x+y=1$
Work Step by Step
$3x+y=1$
$2y=2-6x$
$2y=2-6x$
$2y+6x=2-6x+6x$
$6x+2y=2$
$3x+y=1$
$6x+2y=2$
Please see the screenshot showing the steps for Cramer's rule.
Since we have zeroes for $D$, $D_x$, and $D_y$, we see that there are infinite solutions to the system.