Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix D - Exercise Set - Page 997: 92

Answer

$(-∞,0]\cup[\frac{6}{5},∞)$

Work Step by Step

We simplify as follows: $8+|5x-3|\geq11$ $|5x-3|\geq3$ $5x-3\leq-3$ or $5x-3\geq3$ $x\leq0$ or $x\geq\frac{6}{5}$ $(-∞,0]\cup[\frac{6}{5},∞)$
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