Answer
$(-∞,0]\cup[\frac{6}{5},∞)$
Work Step by Step
We simplify as follows:
$8+|5x-3|\geq11$
$|5x-3|\geq3$
$5x-3\leq-3$ or $5x-3\geq3$
$x\leq0$ or $x\geq\frac{6}{5}$
$(-∞,0]\cup[\frac{6}{5},∞)$
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