Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - 9-4 Arithmetic Series - Practice and Problem-Solving Exercises - Page 593: 66

Answer

$\frac{c - 2}{c - 5}$ Restriction: $c \ne 6, 5$

Work Step by Step

Factor all expressions in the original exercise: $\frac{(c - 6)(c - 2)}{(c - 6)(c - 5)}$ Cancel common factors in the numerator and denominator: $\frac{c - 2}{c - 5}$ Restrictions on $c$ occur when the value of $c$ makes the denominator equal $0$, which means that the denominator becomes undefined. Set the factors in the denominators equal to $0$ to find restrictions: First factor: $c - 6 = 0$ Add $6$ to each side of the equation: $c = 6$ Second factor: $c - 5 = 0$ Add $5$ to each side of the equation: $c = 5$ Restriction: $c \ne 6, 5$
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