Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - 9-3 Geometric Sequences - Practice and Problem-Solving Exercises - Page 586: 67

Answer

The points of discontinuity occur at $x = -5$ and $x = -1$.

Work Step by Step

Points of discontinuity occur where the denominator becomes undefined, which means that the denominators equal $0$. Set each factor in the denominator equal to $0$ and solve for $x$ to find the discontinuities in this exercise: First factor: $x + 5 = 0$ Subtract $5$ from each side of the equation: $x = -5$ Second factor: $x + 1 = 0$ Subtract $1$ from each side of the equation: $x = -1$ The points of discontinuity occur at $x = -5$ and $x = -1$.
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