Answer
$(x+3)(x-2)$
Work Step by Step
Recall:
$x^2+bx+c=(x+d)(x+e)$ where $b=d+e$ and $c=d\cdot e$.
The given trinomial has $b=1$ and $c=-6$.
Note that:
$6=3(-2)$
and
$1=3+(-2)$.
This means that $d=3$ and $e=-2$.
Hence, the factored form of the given trinomial is:
$$x^2+x-6=(x+3)(x-2)$$
