Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - 8-1 Inverse Variation - Practice and Problem-Solving Exercises - Page 504: 30

Answer

$x=2$

Work Step by Step

Recall: A direct variation is represented by the equation $y=kx$, where $k$ is the constant of variation. As the value of $x$ increases, the value of $y$ also increases. The equation that models the direct variation can be determined by solving the value of $k$: This can be done by taking any ordered pair $(x, y)$ then substituting the values of $x$ and $y$ into the direct variation formula $y=kx$. Since the variation contains the point $(4, 6)$, substitute these into the formula $y=kx$ to obtain: \begin{align*} y&=kx\\\\ 6&=k(4)\\\\ \frac{6}{4}&=k\\\\ 1.5&=k\end{align*} Therefore, the equation that models the direct variation is $y=2.5x$. To find the value of $x$ when $y=3$, substitute $3$ to $y$ in the equation above to obtain: \begin{align*} y&=1.5x\\\\ 3&=1.5x\\\\ \frac{3}{1.5}&=\frac{1.5x}{1.5}\\\\ 2&=x \end{align*}
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