Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Review - Page 488: 18

Answer

$\$1,100.76$

Work Step by Step

Recall: The formula for interest that compounds continuously is: $$A=Pe^{rt}$$ where $P$ = principal amount invested $r$ = annual interest rate $t$ = time in years Using the given values and the formula above gives: \begin{align*} A&=Pe^{rt}\\ &=1000e^{4.8\% \cdot 2}\\ &=1000e^{0.048\cdot 2}\\ &=1000e^{0.096}\\ &\approx 1100.76 \end{align*} Thus, the valule of the investment after $2$ years is approximately $\$1,100.76$
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