Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 425: 45

Answer

$x=15$

Work Step by Step

Divide $3$ to both sides: \begin{align*} \dfrac{3\sqrt{2x+6}}{3}&=\dfrac{18}{3}\\\\ \sqrt{2x+6}&=6\\ \end{align*} Square both sides: \begin{align*} (\sqrt{2x+6}^2&=6^2\\\\ 2x+6&=36 \end{align*} Solve for $x$: \begin{align*} 2x&=36-6\\\\ 2x&=30\\\\ \frac{2x}{2}&=\frac{30}{2}\\\\ x&=15 \end{align*}
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