Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-7 Inverse Relations and Functions - Practice and Problem-Solving Exercises - Page 412: 81

Answer

$h(x) + g(x) = -\frac{3}{2}x+ 11$

Work Step by Step

In this problem, we are asked to add two functions. Let us go ahead and set up the addition problem, separating the two functions with parentheses: $h(x) + g(x) = (-2x + 4) + (\frac{1}{2}x + 7)$ Remove the parentheses, but pay attention to the operation in front of the parentheses: $h(x) + g(x) = -2x + 4 + \frac{1}{2}x + 7$ Group like terms: $h(x) + g(x) = (-2x + \frac{1}{2}x) + (4 + 7)$ Subtract fractions by finding equivalent fractions that have the same denominator: $h(x) + g(x) = (-\frac{4}{2}x + \frac{1}{2}x) + (4 + 7)$ Combine like terms: $h(x) + g(x) = -\frac{3}{2}x+ 11$
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