Answer
$9x^2+12x+40+\dfrac{120}{x-3}$
Work Step by Step
Using the long division method below, the given expression, $
(9x^3-15x^2+4x)\div(x-3)
,$ is equal to
\begin{align*}
9x^2+12x+40+\dfrac{120}{x-3}
.\end{align*}
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