Answer
There are no real solutions to this system of equations.
Work Step by Step
Use the expressions given for $x$ and $y$ to substitute into the first equation:
$(-3z + 6) + 2(z + 1) + z = 14$
Distribute first:
$-3z + 6 + 2z + 2 + z = 14$
Group like terms:
$(-3z + 2z + z) + (6 + 2) = 14$
Combine like terms:
$0 + 8 = 14$
Simplify:
$8 = 14$
This statement is false; therefore, there are no real solutions to this system of equations.
