Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-6 Solving Systems Using Matrices - Practice and Problem-Solving Exercises - Page 181: 55

Answer

The solutions are $x = 10$ and $x = -10$.

Work Step by Step

Use the rule $|x|=a \implies x=a \text{ or } x=-a$ to obtain: $4x = 40$ or $4x = -40$ Now solve each equation. For the first equation: $4x = 40$ Divide both sides of the equation by $4$ to solve for $x$: $x = 10$ For the second equation: $4x = -40$ Divide both sides of the equation by $4$ to solve for $x$: $x = -10$ Checking: For $x=-10$: \begin{align*} |4(-10)|&=40\\ |-40|&=40\\ 40&=40\\ \end{align*} For $x=10$: \begin{align*} |4(10)|&=40\\ |40|&=40\\ 40&=40\\ \end{align*} Thus, the solutions are $x = 10$ and $x = -10$.
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