Answer
$f(6)=2$ and $ f(11)=2$
Work Step by Step
Here as the function is periodic, for every $x=1+5k$ and $x=1-5k$ where $k=Z$(Integers) we get $f(x)=2$
Here, as $6$ can be written as $1+5*1$ and $11$ can be written as $1+5*2$
We get $f(6)=2$ and $ f(11)=2$