Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - Get Ready! - Page 761: 3

Answer

$ad-bc=-\dfrac{3}{8}$

Work Step by Step

Substituting $ a=2 ,$ $ b=\dfrac{1}{2} ,$ $ c=\dfrac{1}{4} ,$ $ d=-\dfrac{1}{8} $ in the expression $ad-bc,$ then \begin{align*}\require{cancel} & \left( 2 \right)\left( -\dfrac{1}{8} \right)-\left( \dfrac{1}{2} \right)\left( \dfrac{1}{4} \right) \\\\&= -\dfrac{2}{8}-\dfrac{1}{8} \\\\&= -\dfrac{3}{8} .\end{align*} Hence, $ ad-bc=-\dfrac{3}{8} $.
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