Answer
$\frac{3}{40}$
Work Step by Step
Determinant of any matrix: $\begin{bmatrix} a&b \\ c&d \end{bmatrix}$ = $ad-bc$
$det(\begin{bmatrix} \frac{3}{10}&\frac{1}{5} \\ \frac{1}{8}&\frac{1}{3} \end{bmatrix})$ = $\frac{3}{10}*\frac{1}{3}-\frac{1}{5}*\frac{1}{8} = \frac{1}{10}-\frac{1}{40} = \frac{3}{40}$
