Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-2 Probability - Practice and Problem-Solving Exercises - Page 686: 21

Answer

$\frac{3}{4}$

Work Step by Step

For mutually exclusive events, $P(S\text{ and T}) = 0$, so we have: $$\begin{aligned} P(S\text{ or }T)& = P(S) + P(T) - P(S\text{ and }T) = P(S) + P(T)\\ P(S\text{ or }T)&= \frac{5}{8} + \frac{1}{8}\\ & = \frac{6}{8}\\ & = \frac{3}{4}. \end{aligned}$$
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