Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 8 Rational Functions - Chapter Review - Page 606: 31



Work Step by Step

We use cross multiplication to solve. Doing this, we find: $$2x\left(4x-3\right)=-\left(x+4\right)\cdot \:3x \\ x=0,\:x=-\frac{6}{11}$$ Checking, we see that $x=-\frac{6}{11}$ is extraneous.
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