Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Standardized Test Practice - Gridded Answer - Page 547: 12



Work Step by Step

The continuous compounding formula $A=Pe^{rt}$ Given: $P=500\\r=0.035\\t=1$ Plug in the data: $A_1=500e^{0.035(1)}\approx 17.81$
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