Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Standardized Test Practice - Extended Response - Page 547: 22b

Answer

See below

Work Step by Step

Given: $P=14.7e^{-0.0004h}$ Solving $h$ for $P=12$, we have: $12=14.7e^{-0.0004h}\\e^{-0.0004h=\frac{12}{14.7}}\\\ln e^{-0.00044h}=\ln\frac{12}{14.7}\\-0.0004h=\ln\frac{12}{14.7}\\h\approx507.35 ft$
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