Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Review - Page 541: 31

Answer

$$\ln \left(36\right)$$

Work Step by Step

Using the rules of logarithms, we find: $$\ln \left(3^2\right)+5\ln \left(2\right)-\ln \left(8\right) \\ \ln \left(3^2\right)+\ln \left(2^5\right)-\ln \left(8\right) \\ \ln \left(2^5\cdot \:3^2\right)-\ln \left(8\right) \\ \ln \left(\frac{288}{8}\right) \\ \ln \left(36\right)$$
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