Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.5 Graph Square Root and Cube Root Functions - 6.5 Exercises - Problem Solving - Page 450: 37b

Answer

See below

Work Step by Step

From part a, we found: $v=331.5\sqrt \frac{273.15+C}{273.15}$ Since $K\geq 0$ and $K=273.15+C$ then $273.15+C\geq0\\ C\geq-273.15$ The domain of the function is $C\geq-273.15$. The range of the function is $v \geq 0$.
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